3 years ago

Which equation can be used

Mathematics

1 answer:

avanturin [10]3 years ago

6 0

The first one I think

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What is the speed (approximately) of a 2.5-kilogram mass after it has fallen freely from rest through a distance of 12 meters?

Norma-Jean [14]

Answer:

15.3 m/s

Step-by-step explanation:1) Find the gravitational potential energy using the equation :

$PE_g=mgh$

$PE_g=2.5(12)(9.8)\\PE_g=294$

2) Then use the equation for kinetic energy to solve for the velocity:

$KE=\frac{1}{2} mv^{2}$

$294=\frac{1}{2}(2.5)(v^2)\\235.2=v^2\\\sqrt{235.2} =v\\15.3 m/s=v$

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3 years ago

6. f(x) = x ^ 2 + 2x g(x) = 3x ^ 2 - 1

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

42 < 21+3x < 84

21 < 3x < 63

7 < x < 21

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3 years ago

there are 8 quarts in a peck and 4 pecks in one bushel.What is the first thing you need to do if you are asked to find how many

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Step-by-step explanation:

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3 years ago

Find the distance between the points (2, 7) and (-6, -2).

maw [93]

Answer:

Approximately 12.04 units.

Step-by-step explanation:

The find the distance between any two points, we can use the distance formula, which is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

We have the points (2,7) and (-6,-2). Let's let (2,7) be (x₁, y₁) and let's let (-6, -2) be (x₂, y₂). Substitute:

$d=\sqrt{(-6-2)^2+(-2-7)^2$

Subtract:

$d=\sqrt{(-8)^2+(-9)^2$

Square:

$d=\sqrt{64+81}$

Add:

$d=\sqrt{145}$

Approximate

$d=\sqrt{145}\approx12.04$

So, the distance between (2,7) and (-6,-2) is approximately 12.04 units.

And we're done!

7 0

4 years ago