Answer:
Step-by-step explanation:
The answer is 24. it works like this. you subtract 2 from 12 and get 10. then add 5 to 10 to get 15. then subtract 2 from 15 and get 13. 13+5 is 18. and so on
if its diameter is 14, then its radius is half that or 7.
![\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (7)^3}{3}\implies V=\cfrac{1372\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V\approx 1436.03} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20V%3D%5Ccfrac%7B4%5Cpi%20%287%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B1372%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%5Capprox%201436.03%7D%20%5Cend%7Barray%7D)
Answer:
Please look at the attachment for the figure of circle with radius, diameter,circumference labelled.
AB is the diameter
OB and OA are radii
Radius is half of the diameter or in other words diameter is double of radius.
And circumference is the outer line of the circle

Answer:
See below ~
Step-by-step explanation:
Question 6(e) :
⇒ x² ≤ 16
<em>Take square root on each side :</em>
⇒ √x² ≤ √16
⇒ x ≤ 4 and x ≥ -4
⇒ -4 ≤ x ≤ 4