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Goshia [24]
3 years ago
6

Solve for c.

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0
The answer is c = (5 - b)/3ab

<span>3abc + b = 5

Subtract b from both sides:
3abc + b - b = 5 - b
3abc = 5 - b

Divide both sides by 3ab:
3abc/3ab = (5 - b)/3ab
c = </span>(5 - b)/3ab
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What is the slope of the line that passes through the points (1, 3) and (5, –2)?
Sergeu [11.5K]

m=-(5/4)

From left to right, (1,3) is first and then comes (5,-2). Always remember when finding slopes without equations, the rule is RISE over RUN, to the numerator and denominator, respectively.

The y value of the second coordinates becomes negative which is unlike the y value in the first coordinates, which means our slope is downward, meaning it has a negative sign in front.

In every slope, there’s a numerator, being the rise, and a denominator, being the run.

To find the rise, we must look at the y values. Starting at 3 going to -2 has a space of 5 units, making that our numerator.

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2 years ago
Very confused with this
OlgaM077 [116]

Answer:

∠ D = 28°

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The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBC is an exterior angle of Δ ABE, thus

∠ EBC = 90° + 34° = 124°

BD bisects ∠ EBC, so

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2 years ago
Use the given conditions to write an equation for the line in point-slope form and slope-intercept form.
alexandr402 [8]

Answer:

slope-inercept form: y = 3x + 3        point-slope form: y - 9 = 3(x - 2)

Step-by-step explanation:

slope-intercept form:

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y - 9 = 3(x - 2)

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