Question

Frank left his house at 7 a.m. and drove to the airport at a speed of 50 mph. Lance left his house at 6 a.m. and drove to the same airport at a speed of 55 mph. Frank's house is 150 miles from the airport and Lance's house is 220 miles from the airport.
At what time did Lance arrive at the airport?

Answer 1

Answer:

Lance will arrive at the airport at 10:00 AM.

Step-by-step explanation:

Lance left his house at 6:00 AM, and drove to the airport, which is 220 miles away, at 55mph; therefore, the time $t$ it takes Lance to cover the distance of 220 miles is

$t = \dfrac{220m}{55mph}$

$t= 4 \: hours.$

Thus, it takes Lance 4 hours to reach the airport, and since he departed at 6:00 AM, he will arrive at the airport at (6+4):00 AM + 10:00 AM.