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Bogdan [553]
3 years ago
11

Write an expression that, when simplified, is equivalent to 15x + 7

Mathematics
1 answer:
Alona [7]3 years ago
4 0
Sdadadasdasdasdasdasd9979797979759
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Determine the correct scientific notation form of the number. 327,000,000,000
I am Lyosha [343]

Answer:

B. 3.27 x 10^11.

Step-by-step explanation:

There are 11 digits after the first one, so it is

3.27 x 10^11.

5 0
3 years ago
What is the range of the function represented by these ordered pairs?
GrogVix [38]

Answer:

  • {-1, 0, 1, 7}

Step-by-step explanation:

<u>Set of ordered pairs</u>

  • {(–2, 1), (0, 0), (3, –1), (–1, 7), (5, 7)}

<u>Range of the function is the second numbers of the pairs:</u>

  • 1, 0, - 1, 7, 7

<u>Putting them in set notation in ascending order and ignoring duplicates:</u>

  • {-1, 0, 1, 7}

8 0
3 years ago
Read 2 more answers
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 18 Pennies13 Dimes 18 Nickels1
Nezavi [6.7K]

Answer:

P(Nickel\ and\ Nickel) = 0.08091

Step-by-step explanation:

Given

Pennies = 18

Dimes = 13

Nickels = 18

Quarters = 13

Required

Probability of selecting 2 nickels without replacement

This can be represented as: P(Nickel\ and\ Nickel)

The solution is as follows

P(Nickel\ and\ Nickel) = \frac{Nickel}{Total}*\frac{Nickel-1}{Total-1}

The second nickel is reduced by 1 because the first nickel was not replaced and this also reduces the total by 1

So, we have:

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{18-1}{62-1}

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{17}{61}

P(Nickel\ and\ Nickel) = \frac{18*17}{62*61}

P(Nickel\ and\ Nickel) = \frac{306}{3782}

P(Nickel\ and\ Nickel) = 0.08091

6 0
3 years ago
Question
kirill [66]

Answer: 40 mg

Unitary method:

For 3kg --> 8mg

For 1kg --> 8/3 mg

For 15kg--> (8/3) * 15

              --> 40 mg

7 0
2 years ago
If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?
Ierofanga [76]

Answer:

it's -4 I just took the test and you will get it write

6 0
4 years ago
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