Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Answer:
8/25 simplified
Step-by-step explanation:
The first eight multiples of the number six are 6, 12, 18, 24, 30, 36, 42 and 48. Multiples are obtained by multiplying a number by integers, so the multiples of 6 can be obtained by multiplying 6 by integers starting from 1.
Hope this helps
Parallel lines have the same slope, so the slope is 5
in point=slope form: (y-2)=5[(x-(-3)]
y-2=5(x+3)
in slope intercept form: y=5x+17
in standard form: 5x-y=-17
