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Bumek [7]
3 years ago
13

A cable company charges $75 for installation plus $20 per month. Another cable company offers free installation but charges $35

per month. For how many months of cable service would the total cost from either company be the same?
(a) 5
(b) 7
(c) 2
(d) 3
Mathematics
2 answers:
uranmaximum [27]3 years ago
7 0
Your answer would be (A) :)
kifflom [539]3 years ago
3 0
It would be 5 months because if you do 75 + 20x = 35x
15x = 75
----- ------
15 15
x = 5
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(x-1)^2+(2-x)^2-3(x-5)*(x-5)
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Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

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