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3 years ago

Which number is 5 more than 2? Which number is 4 less than -3? PLS HELP ME ILL GIVE YOU BRAINLIST

Mathematics

2 answers:

egoroff_w [7]3 years ago

7 0

5 more than 2 is 7, and 4 less than -3 is -7

vaieri [72.5K]3 years ago

6 0

5+2=7 4- -3= -7 hdkb sus heyitsme

You might be interested in

Problem 2. A random variable has the following density function:

kolbaska11 [484]

If f(x) is a density function, then its integral over the entire real line should be 1:

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2(1-0.5x)\,\mathrm dx=(x-0.25x^2)\bigg|_0^2=2-1=1$

so yes, f(x) is indeed a density function.

6 0

3 years ago

M/8 = 4 Solve for m m = ?

fomenos

Answer: m = 32

Step-by-step explanation:

32 divided by 8 = 4

7 0

3 years ago

Read 2 more answers

Write down and simplify all the terms in the expansion of (1+3x)6.Using your results to estimate the value of (0.97)6correct to

Keith_Richards [23]

Answer:

$(a)\ (1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1$

$(b)\ (1 + 3(-0.01))^6 = 0.8330$

Step-by-step explanation:

Given

$(1 + 3x)^6$

Solving (a): Expand

To do this, we make use of pascal triangle

When the exponent is 6, the factors are: 1, 6, 15, 20, 15, 6 and 1

As a rule, the exponent of 1 will start from 0 and then increase by 1 in each term while the exponent of 3x will start from 6 and then decrease by 1 in each term.

So, we have:

$(1 + 3x)^6 = 1 * 1^0 * (3x)^6 + 6 * 1^1 * (3x)^5 + 15 * 1^2 * (3x)^4 + 20 * 1^3 * (3x)^3 + 15 * 1^4 * (3x)^2 + 6 * 1^5 * (3x)^1 + 1 * 1^6 * (3x)^0$

Expand

$(1 + 3x)^6 = 1 * (3x)^6 + 6 * (3x)^5 + 15 * (3x)^4 + 20 * (3x)^3 + 15 * (3x)^2 + 6 * (3x)^1 + 1 * (3x)^0$

$(1 + 3x)^6 = 1 * 728x^6 + 6 * 243x^5 + 15 * 81x^4 + 20 * 27x^3 + 15 * 9x^2 + 6 * 3x + 1$

$(1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1$

Solving (b): (0.97)^6

Rewrite as:

$(0.97)^6 = (1 - 0.03)^6$

Express -0.03 as 3 * -0.01

$(0.97)^6 = (1 + 3(-0.01))^6$

So, by comparing:

$(1 + 3x)^6$ and $(1 + 3(-0.01))^6$

$x = -0.01$

Recall that:

$(1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1$

This gives:

$(1 + 3(-0.01))^6 = 728(-0.01)^6 + 1458(-0.01)^5 + 1215(-0.01)^4 + 540(-0.01)^3 + 135(-0.01)^2 + 18(-0.01) + 1$

Using a calculator

$(1 + 3(-0.01))^6 = 0.000000000728 -0.0000001458+ 0.00001215 -0.00054 + 0.0135 -0.18 + 1$

$(1 + 3(-0.01))^6 = 0.83297200492$

$(1 + 3(-0.01))^6 = 0.8330$ --- approximated

4 0

3 years ago

ANSWER ASAP!

finlep [7]

The 13th term of the geometric sequence is:

$a_{17} = \frac{13}{8}$

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term.

As a function of the mth term, the nth term can also be given as follows:

$a_n = a_mq^{n - m}$

In this problem, we have that:

$a_{13} = 26, q = \frac{1}{2}$

Hence the 17th term is:

$a_{17} = a_{13}q^{4}$

$a_{17} = 26 \times \frac{1}{16}$

$a_{17} = \frac{13}{8}$

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

7 0

2 years ago

The areas of two similar triangles are 80 square feet and 500 square feet.

Gelneren [198K]

So in order to get the small rectangle big we need a whole number bigger that 1 or an improper fraction so let's cross out the answer choices that don't meet the above requirements!!

A and C are not improper fractions and are less than 1 so they're wrong!!

We can solve by making an equation,

$80x = 500$

So 80 × what will give us 500.

We can do this two ways and I'll show you both!!

$\frac{80x}{80} = \frac{500}{80}$

We can divide both sides by 80 and get,

$x = \frac{25}{4} = 6.25$

Which is answer choice B which makes sense since answer choice D is too small.

Or, we can plug in our two answer choices and see if it checks out to be 500!!

$80( \frac{25}{4} ) = 500$

The above statement is true!!

$80( \frac{5}{2} ) = 500$

The above statement is false since 80 × 5/2 = 200, not 500, the number we need!!

7 0

3 years ago