Question

WILL GIVE BRAINLIEST TO BEST ANSWER- DUE TODAY

Answer 1

• Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, using our equation plug in the values into our equation (a = 1, b = -4, and c = 3):

$x=\frac{4\pm \sqrt{(-4)^2-4*1*3}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-12}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{4}}{2}$

Next, solve the square root:

$x=\frac{4\pm 2}{2}$

Next, you are going to solve this equation twice - once with the  + symbol, once with the - symbol as such:

$x=\frac{4+2}{2}\\\\x=\frac{6}{2}\\\\x=3\\\\\\x=\frac{4-2}{2}\\\\x=\frac{2}{2}\\\\x=1$

Your zeros (x-intercepts) are 3 and 1. These solutions are real and rational.