3 years ago

54 3/11 as a decimal

1 answer:

6 0

54 3/11...

54 is ur whole number
3/11 = 0.27 with a line over the 27 because it is repeating

so ur answer would be : 54.27...with a line over the 27

You might be interested in

What does this < > = mean

Ber [7]

Less than greater than equal Too

8 0

3 years ago

Read 2 more answers

Part A: simplify the expression 6(2k+5)-20 using the distributive properties=-------------

ikadub [295]

Answer:

$160

Step-by-step explanation:

Part A-

Step 1: 6(2k+5) - 20

Step 2: 6(2k) + 6(5) - 20

Step 3: 12k + 30 - 20

4 0

3 years ago

Read 2 more answers

Help Please & thanks!

Travka [436]

Answer:

14 out of the total class of 35 are boys

Step-by-step explanation:

35 / 5 = 7

7 * 2 = 14

3 0

3 years ago

An object is launched vertically in the air at 36.75 meters per second from a 6-meter-tall platform. Using the projectile motion

nasty-shy [4]

I HAVE THE SAME QUESTION

5 0

3 years ago

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago