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mina [271]
3 years ago
13

Please help

Mathematics
2 answers:
jonny [76]3 years ago
8 0

Answer:

(k ∘ p)(x) = 2x²-16x+25

Step-by-step explanation:

attashe74 [19]3 years ago
3 0

Answer:

<h3>(k ∘ p)(x) = 2x²-16x+25</h3>

Step-by-step explanation:

<h3>(k ∘ p)(x) = 2(x-4)²-7</h3><h3 /><h3>(k ∘ p)(x) = 2(x²-8x+16)-7</h3><h3 /><h3>(k ∘ p)(x) = 2x²-16x+32-7</h3><h3 /><h3>(k ∘ p)(x) = 2x²-16x+25</h3>
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Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

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