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3 years ago

Select the graph that best represents the solution set for 5x+1≤11

1 answer:

5 0

$5x+1 \le 11$

$5x+1-1 \le 11-1$ Subtract 1 from both sides

$5x \le 10$

$\frac{5x}{5} \le \frac{10}{5}$ Divide both sides by 5 to isolate x

$x \le 2$

To graph this, draw out a number line. Plot a closed circle at 2 on the number line. The closed circle indicates we include this value in the solution set. This is the endpoint. We shade to the left of the endpoint to represent all of the values smaller than 2. The endpoint is included because of the "or equal to" portion of the inequality sign.

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8,706, 2812<br> What is the value of 7

LiRa [457]

Answer:

7 million is the answer to this question

5 0

3 years ago

How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.

kifflom [539]

<h2><u>QUADRATIC EQUATION</u></h2>

<h2> $\mathbb{ANSWER:}$ </h2>

$\bold{x = 0.8 \: } \: \sf \: {\color{grey}or} \: \: \: \bold{ x= \frac{4}{5} } \\$

$\bold{x = - 6}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

$\bold{Given \: Equation: \color{brown} 5x²+26x-24=0}$

First, add 24 to both sides.

$\bold{5x²+26x-24 - \purple{ 24} = 0 + \purple{24}}$

$\bold{ \implies \: 5x²+26x = 24 }$

Since the coefficient of 5x² is 5, divide both sides by 5.

$\bold{ \frac{5 {x}^{2} + 26x }{5} = \frac{24}{5} } \\$

$\bold{ \implies \: {x}^{2} + \frac{26}{5} x = \frac{24}{5} } \\$

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

$\bold{ {x}^{2} + \frac{26}{5} x + \frac{ \purple{169}}{ \purple{25}}= \frac{24}{5} + \frac{ \purple{169}}{ \purple{25}} } \\$

$\bold{ \implies \:\bold{ {x}^{2} + \frac{26}{5} x + \frac{ 169}{ {25}}= \frac{289}{25} } } \\$

Factor the left side.

$\bold{(x + \frac{13}{5} ) {}^{2} = \frac{289}{25} } \\$

Take square root.

$\bold{x + \frac{13}{5} = ± \: \sqrt{ \frac{289}{25} }} \\$

Then, add (-13)/5 to both sides.

$\bold{x + \frac{13}{5} + \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \: \sqrt{ \frac{289}{25}}} \\$

$\bold{ \: x = \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\$

$\implies \: \underline{ \boxed{ \bold{ \frac{4}{5} } \sf \: \: or \: \: \bold{ x = - 6}}} \\$

_______________❖_______________

3 0

3 years ago

Read 2 more answers

GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

$GJ=\frac{1}{2}DE$