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3 years ago

T/F – Interphase is part of mitosis.

Biology

2 answers:

Maksim231197 [3]3 years ago

8 0

False. Interphase is not technically a part of mitosis.

During interphase, the cell is performing its normal functions and preparing for mitosis.

ryzh [129]3 years ago

8 0

Answer:

It is false.

Explanation:

Mitosis is made up of 4 stages: Prophase, metaphase, anaphase and telophase. The interface is not part of mitosis but of the cell cycle.

The interface is defined as the period between two successive cell divisions. In this stage, the processes of cell functioning take place. In addition, preparatory processes are performed to reach mitosis: DNA duplication, in which the cell doubles in size and increases the number of organelles. At this stage, the DNA is as chromatin.

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Why is it important to know a person blood type before a blood transfusion?

lord [1]

Different types of blood contact different kinds of antigens and antibodies. For example, Type A blood has A antigens and B antibodies, antibodies being the thing that fights B antigens. Type B blood has B antigens and A antibodies. So if someone with type B gets transfused with Type A blood, the person's antibodies will attack the new blood.

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3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

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3 years ago

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Answer:

The act of carefully watching or examining a person or object when something is happening is known as an observation. An act of deriving rational conclusion from known facts or circumstances is called inference. ... On the other hand, the inference is an explanation or assumption of what one has perceived or seen.

Explanation:

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3 years ago

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seraphim [82]

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1 year ago