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frozen [14]
2 years ago
8

Jeff bought a bottle of water for $2. He also some hot dogs for $3 each. Jeff did not spend more than $14 on the hot dogs and th

e bottle of water. Which inequality can be used to find h, the number of hot dogs that Jeff could have bought?
Mathematics
1 answer:
enyata [817]2 years ago
5 0
It’s h is greater than or equal to 4
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(Pts: 1) Please help me! Question is in attachment!
Sloan [31]
- - Solve:

To find the volume of a sphere:
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3.14≈π

Now since its telling us to use π, then we do our formula by multiplying by π.

π=3.14 (Approximate amount)

So:

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So you are correct.

When Radius=9, you plug in for R. :)

8 0
3 years ago
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Crystal has exactly $2.40 in quarters, dimes, and nickers. She has the same number of each type of coin. What is the number?​
Nadya [2.5K]

Answer:

6 quarters, 6 dimes, and 6 nickels

Step-by-step explanation:

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3 years ago
Your team catches 42 Mahi Mahi over 2 weeks. What is the average daily Mahi Mahi catch?
Hunter-Best [27]
2 weeks are 14 days so
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3 years ago
Rewrite 10 + 12 using the GCF and factoring.
Airida [17]

Answer:

1st option

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5 0
1 year ago
A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa
Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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In this problem, the parameters are:

z = 2.575, n = 2000, \pi = 0.77

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
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