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Ksivusya [100]
3 years ago
14

Use the euclidean algorithm to find

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
2463=164\cdot15+3
15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
1596=2\cdot636+324
636=1\cdot324+312
324=1\cdot312+12
312=26\cdot12+0
\implies\mathrm{gcd}(9888,6060)=12
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A professor wants to know whether or not there is a difference in comprehension of a lab assignment among students depending on
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Answer:

It is concluded that no difference exists in the comprehension of the lab based on the test scores.

Step-by-step explanation:

<em><u>Let the populations be normally distributed with a populations standard deviation of 5.32 points for both the text and visual illustrations.</u></em>

The above statement tells us that the independent t or two sample t test will be performed as both have equal variances and are normally distributed.

This can be easily done through excel.

The following table is obtained

     

t-Test: Two-Sample Assuming Equal Variances  

 

                <u>  Text                      Visual Illustrations</u>

Mean          70.28                       75.08

Variance 304.48                     228.58

Observations 15                             15

Pooled Variance Sp²= 266.53

       Pooled Standard Deviation = Sp = 16.33

Hypothesized Mean Difference = x1`-x2`= 0

df = n1+n2-2= 15+15-2= 30-2= 28

t Stat -0.805188239

<u>P(T<=t) two-tail 0.427495979                      </u>

<u>t Critical two-tail 1.701130908                              </u>

Let the null and alternate hypotheses be

H0 : u1-u2= 0   against the claim Ha: u1-u2≠0

There is no difference between the means

against the claim

that there is a difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

The significance level is ∝= 0.1

The d.f is n1+n2-2= 15+15-2= 30-2=28

This is a two tailed test and the critical region is t (0.025) (28) ≥ 1.7011 and  t (0.025) (28) ≤ - 1.7011.

The test statistic is

t= x1-x2/ Sp √1/n1+ 1/n2

t= 70.28 -75.08/ 16.33√1/15 +1/15

t= -4.8/5.963

t= -0.8049811  ( minute difference from excel result due to rounding)

Since the calculated value of t= -0.8049 does not fall in the critical region we conclude that there is no difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

We accept the null hypothesis.

The p- value is 0.427495979.

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