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Ksivusya [100]
3 years ago
14

Use the euclidean algorithm to find

Mathematics
1 answer:
kvasek [131]3 years ago
8 0
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
2463=164\cdot15+3
15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
1596=2\cdot636+324
636=1\cdot324+312
324=1\cdot312+12
312=26\cdot12+0
\implies\mathrm{gcd}(9888,6060)=12
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Scores on a certain IQ test are knownto have a mean of 100. A random sample of 43 students attend a series of coaching classes b
NeX [460]

Answer:

Part 1

Type II error

Part 2

No ; is not ; true

Step-by-step explanation:

Data provided in the question

Mean = 100

The Random sample is taken = 43 students

Based on the given information, the conclusion is as follows

Part 1

Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis

Based on this, it is a failure to deny or reject the false null that represents type II error

Part 2

And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible

Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful

6 0
3 years ago
Which is the graph of the sequence defined by the function f(x + 1) = Three-fifthsf(x) when the first term in the sequence is 37
nadezda [96]

Answer: On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

Step-by-step explanation:

We have the relation:

f(x + 1) = (3/5)*f(x)

such that the first term is 375

Then:

f(1) = 375.

Using the above relation, we have that:

f(1 + 1) = f(2) = (3/5)*f(1) = (3/5)*375 = 225

Then we have the pair (2, 225)

The next term is:

f(2 + 1) = f(3) = (3/5)*f(2) = (3/5)*225 = 135

Then we have the pair (3, 135)

the next term is:

f(3 + 1) = f(4) = (3/5)*f(3) = (3/5)*135 = 81

Then we have the pair (3, 81)

Then the correct option is the first one; On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

9 0
3 years ago
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Please help will brainlest
liubo4ka [24]

Answer:

1. =  32z4s7     2.= 20w9    3.= 15r6    8.= 9c6z3 (i don't know 9 sorry)            10.= 8h9c2

Step-by-step explanation:

the numbers that come AFTER the letters are the powers.

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3 years ago
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