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belka [17]
3 years ago
5

Anyone know how to do this?

Mathematics
2 answers:
juin [17]3 years ago
6 0

Answer:yes

Step-by-step explanation:

joja [24]3 years ago
6 0
You know it’s a real number because you can have a number take the spot of i to make it continuous
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If a, b, c are in continued proportion, then a sq.= bc.​
snow_tiger [21]

photo math is the solution of your problems hehehehehehe try it!!!

3 0
3 years ago
-4 (r + 2) = 4 (2 - 2r)
Nady [450]

Answer:

r=4

Step-by-step explanation:

Let's solve your equation step-by-step.

−4(r+2)=4(2−2r)

Step 1: Simplify both sides of the equation.

−4(r+2)=4(2−2r)

(−4)(r)+(−4)(2)=(4)(2)+(4)(−2r)(Distribute)

−4r+−8=8+−8r

−4r−8=−8r+8

Step 2: Add 8r to both sides.

−4r−8+8r=−8r+8+8r

4r−8=8

Step 3: Add 8 to both sides.

4r−8+8=8+8

4r=16

Step 4: Divide both sides by 4.

4r

4

=

16

4

r=4

Answer:

r=4

3 0
3 years ago
Please help with this!
egoroff_w [7]

Answer:

u gotta divide the 7.5% and the other number that is says (can see the question but there)

8 0
3 years ago
If A denotes some​ event, what does Upper A overbar ​denote? If ​P(A)equals0.999​, what is the value of ​P(Upper A overbar​)? Wh
meriva

Answer:

<h3>The event P(\overline{A}) denotes the complement of event A.</h3><h3>The value of P(\overline{A}) is 0.001</h3>

Step-by-step explanation:

Given that A denotes some event .

And also given that P(A)=0.999

<h3>To find the value of P(\overline{A}) :</h3>

Here the event P(\overline{A}) denotes the complement of event A Therefore P(\overline{A}) contains all the events that does not occur in A.

We know that the total probability is 1

So we have that

P(A)+P(\overline{A})=1

P(\overline{A})=1 -P(A)

=1-0.999

=0.001

Hence the complement of event A is P(\overline{A})=0.001

<h3>Therefore the value is P(\overline{A})=0.001</h3>

6 0
3 years ago
15 crackers weigh 69 grams. how many kilograms is this?
Marrrta [24]

Answer:

0.069\ kg

Step-by-step explanation:

we know that

1 kg=1,000 g

so

using proportion

Find out how many kilograms are 69 grams

Let

x -----> the weight in kg

\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg

6 0
4 years ago
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