The answer is as follow
sin60° = 400√3 / H1, implies H1= 400√3 / sin60° <span>
sin30° = </span>400√3 / H2, implies H2= 400√3 / sin30° <span>
and the if the distance is D,
so we can find D such that D= H2 - H1=</span>400√3 / sin30° - 400√3 / <span>sin60°
D= </span>400√3(1/sin30° - 1/ sin60°)=400√3(2-1.15)=338.11<span>√3</span>
The answer is 5x-59
To get this answer you have to follow pemdas and remember you can’t add variables to non variables, so you just expand the equation
As an example
5x + 6 -2x +7
You would get
13-3x
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
Answer:

Step-by-step explanation:
Given


Required
Write an expression for the area of new post office
From the question, we have the following:

and

Substitute p for Area of Old in the second equation


Hence, the expression is:
