By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
To learn more on quadratic equations: brainly.com/question/17177510
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Answer:
x= 2 and y = -4
Step-by-step explanation:
8x + 3y = 4 ---------------------------------(1)
-7x + 5y = -34 -----------------------------(2)
Multiply through equation (1) by 5 and multiply through equation(2) by 3
40x + 15y = 20 ----------------------------(3)
-21x + 15y =-102----------------------------(4)
Subtract equation (4) from equation (3)
61x = 122
Divide both-side of the equation by 61
61x/61 = 122/61
(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)
x = 122/61
x=2
Substitute x= 2 into equation (1)
8x + 3y = 4
8(2) + 3y = 4
16 + 3y = 4
Subtract 16 from both-side of the equation
16-16 + 3y = 4-16
3y = -12
Divide both-side of the equation by 3
3y/3 = -12/3
y = -4
x= 2 and y = -4
