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2 years ago

Can someone please help me? Will give the brainlest!!

Mathematics

1 answer:

SCORPION-xisa [38]2 years ago

5 0

Step-by-step explanation:

The ratio of the perimeters = the scale

P₂ / P₁ = 6 / 4 = 3 / 2

The ratio of the areas = the square of the scale

A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4

Same for the triangles:

P₂ / P₁ = 6 / 3 = 2

A₂ / A₁ = (6 / 3)² = (2)² = 4

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

dolphi86 [110]

Answer:

Length = 17 inches

Width = 12 inches

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Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

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Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

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Now, <u>According to the Question :</u>

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${\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}$

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${\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 58 - 10}}}}$

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${\longrightarrow \qquad { {\sf{ 4x = 48}}}}$

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${\longrightarrow \qquad { {\sf{ x = \dfrac{48}{4} }}}}$

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${\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\: \: \bigstar$

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Therefore,

The width of the rectangle is 12 inches .

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Now, We are to find the length of the rectangle:

${\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}$

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${\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}$

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Therefore,

The length of the rectangle is 17 inches .

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8 0

1 year ago

Read 2 more answers

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

Lemur [1.5K]

Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

5 0

3 years ago

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Can someone solve this

RSB [31]

a) 110°

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7 0

1 year ago

PLEAASE HELP ME FAST!!! HELP FAST!

Helen [10]

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3 years ago

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Elena is going to mow lawns for the summer to make some extra money. She will charge $20 for every lawn she mows and plans on mo

sesenic [268]

Answer:

Kx20=N

Step-by-step explanation:

k with be the number multiplied by 20 and then N will be the answer

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2 years ago