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AveGali [126]
3 years ago
11

Can someone please help me? Will give the brainlest!!

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Step-by-step explanation:

The ratio of the perimeters = the scale

P₂ / P₁ = 6 / 4 = 3 / 2

The ratio of the areas = the square of the scale

A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4

Same for the triangles:

P₂ / P₁ = 6 / 3 = 2

A₂ / A₁ = (6 / 3)² = (2)² = 4

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Answer: C) an occluded front leading to a tropical storm

Step-by-step explanation: it is occluded because the two cool and warm fronts are joined together creating a tropical storm.

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Of the line of what?
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Spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 62.1
Marta_Voda [28]
Caution:  you need to use the same units of measurement throughout.  If the spring stretches by 21 cm when a 135 newton object is attached, then you must ask for the mass (in newtons) of a fish that would stretch the spring by 62.1 cm.

We will need to assume that the spring is not stretched at all if and when no object is attached to the spring.

Write the ratio

                21.0 cm        135 newtons
               ------------- = --------------------
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Solve this for x.  This x value represents the mass of a fish that would stretch the spring by 62.1 cm.  You can cancel "cm" in the equation above:

21.0      135 newtons
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62.1               x

Then 21.0x = (62.1)(135 newtons).  Divide both sides of this equation by 21.0 to solve it for x.
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3 years ago
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HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

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vichka [17]

3m - 5n + 6m - 8n \\ 3m + 6m - 5n - 8n \\ 9 m- 13n

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