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neonofarm [45]
3 years ago
13

a line segment from one side of a circle to the other side of the circle going through the center of circle is called the

Mathematics
1 answer:
KIM [24]3 years ago
4 0

It is the diameter .

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What is the answer to 3(5)​
zmey [24]

Answer: 15

Step-by-step explanation:

3x5=15

4 0
3 years ago
Read 2 more answers
If a → b is true, then ~a → b is also true.
Rasek [7]

Answer:

False

Step-by-step explanation:

To determine whether the statemaent "If a\Rightarrow b is true, then \neg a\Rightarrow b is also true" holds, you can form the truth table:

\begin{array}{ccccc}a&b&a\Rightarrow b&\neg a&\neg a\Rightarrow b\\1&1&1&0&1\\1&0&0&0&1\\0&1&1&1&1\\0&0&1&1&0\end{array}

When the result of the column a\Rightarrow b takes value 1 (true), the result of the column  \neg a\Rightarrow b is not always 1, then the statement is false.

7 0
3 years ago
You increase the size of a page by 30%. Then you decrease it by 30%. What is the size of the page now?
kotegsom [21]
Lets use 1 to solve this problem because it is easiest to show. 

Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3). 

Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)  

Therefore the page had a 9% reduction from its original size or is 91% of its original size. 
8 0
2 years ago
Read 2 more answers
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Round 14,445 to the nearest hundred
Bumek [7]

Answer:

the answer is 14,400

Step-by-step explanation:

7 0
2 years ago
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