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antiseptic1488 [7]
3 years ago
13

Maya is trying to break or tie the league record for home runs in her softball league. She solved the inequality mc019-1.jpg to

find the minimum number of home runs she must average per week over the five remaining weeks of the season to break or tie the record. What error did Maya make when she chose this inequality to model the situation?
She chose the incorrect relation and should have solved 5x<30

She modeled “average” incorrectly and should have solved x/5<_30

She chose the incorrect relation and should have solved 5x_>30

She modeled “average” incorrectly and should have solved x+5<_30
Mathematics
2 answers:
Lelechka [254]3 years ago
7 0
The correct answer would be letter C. She needs to either break or tie the record. The less than or equal to symbol in the original inequality would be her scoring less or tying the record. Using the greater than or equal to sign would represent her breaking the record or tying with it. Hope this helped.
Sladkaya [172]3 years ago
4 0

Answer:

c

Step-by-step explanation:

me smart birb

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The basketball player Shaquille O'Neal is 7 feet 1 inch tall, which is equivalent to 216 centimeters a nanometer (nm) is a unit
Kamila [148]

Answer:

Shaquille O'Neal's height= 2,160,000,000 nm

= 2.16 × 10^9 nm

Completed question;

The basketball player Shaquille O'Neal is 7 feet 1 inch tall, which is equivalent to 216 centimeters a nanometer (nm) is a unit of measurement that is one-billionth of a meter, convert his height to nanometers.

Step-by-step explanation:

Given;

Shaquille O'Neal's height= 216cm = 216 × 1/100 m = 2.16m

Since, a nanometer (nm) is a unit of measurement that is one-billionth of a meter.

1 m = 1 billion nanometers

So,

2.16m = 2.16 billion nm = 2160000000 nm

Shaquille O'Neal's height= 2160000000 nm

= 2.16 × 10^9 nm

8 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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