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aleksklad [387]
2 years ago
11

Given f(x) and g(x) = k·f(x), use the graph to determine the value of k

Mathematics
1 answer:
k0ka [10]2 years ago
4 0

Answer:

k=-5

Step-by-step explanation:

If we observe the graph carefully there are two on each of the graphs highlighted at x=-2.The functions take the following values at that x.

f(-2)=2

g(-2)=-10

given the condition

g(x)=k*f(x)

put x=-2

we get . -10=k*2

k=-5

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Answer:

318

Step-by-step explanation:

318 is the required answer

I hope it helped you

So given Figure we need to find total surface area

=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)

=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)

From figure,

AB=DC=PQ=SR=9 cm

BQ=CR=AP=DS=11 cm

BC=AD=QR=SP=3 cm

On substituting these values We get

Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)

=27+33+27+33+99+99=318

I hope it helped you

4 0
1 year ago
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Tanzania [10]
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Which line segment is a radius of circle A?
liubo4ka [24]

AB and AC ................................

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2 years ago
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Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
3 years ago
Help please
Setler79 [48]

Answer: inconsistent

Step-by-step explanation:

Inconsistent systems have two lines that are two independent equations that don’t overlap. Basically, if the lines are parallel, the system will always be inconsistent.

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