A sample of 4 different calculators is randomly selected from a group containing 17 that are defective and 37that have no defect
1 answer:
Answer: 0.8025
Step-by-step explanation:
Given : The number of defective calculators : 17
The number of calculators are not defective : 37
Total calculators : 37+17=54
The probability of the calculators are defective :
Binomial distribution formula :-
, where P(x) is the probability of success in x trials, n is total trials and p is the probability of success for one trial.
The probability that at least one of the calculators is defective is given by :-
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The answer is: " 36 " .
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Note: " (8 * 4) + 90 ÷ 9 " = " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .
We can rewrite the "fraction":
7 / [ (8 * 4) + 90 ÷ 9 ] ; as:
;
and can reduce this value to (and rewrite as): "
" ;
{ since: " = 
= " .}.
Note: The "fraction" :
; the "9/6" cancel to "3/2" ;
{Since: "9÷3 = 3" ; and since: "6÷3 = 2" ).
So rewrite: ; as:
;
Note: ;
=
;
=
;
→ Note: ; can be reduced to; & rewritten as:
"
" ;
→ {since: " = 
;
= ;
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Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴ ;
=
;
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So, we can rewrite our expression as:
÷ * ;
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Note:
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÷ * ;
= ( ÷ ) * ;
= ( * 
) * ;
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Start with :
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→ ( * ) ;
The "6" in the " " ; cancels to a "1" ;
and the "6⁴ " in the " ) " ; cancels to a "6³ " ;
→ {Since: "6⁴ / 6 = 6⁴ / 6¹ = 6⁽⁴ ⁻ ¹⁾ = 6³ ;
→ and we have:
* 
;
→ The " " can be eliminated; since "1÷1= 1 " ;
and since: any value, divided by "1", equal that same value; & since "any value, multiplied by "1"; equals that same value" ;
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We have: " 6³ " .
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Now, we multiplied this value, " 6³ " , by " " ;
→ 6³ * ;
= * ;
Note: The "6³ " cancels out to "6² " ; and the "6" cancels out to "1" ;
{since: "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
and since: "6 ÷ 6 = 1 " ; ________________________________________________________
→ The answer is: 6² = 6 * 6 = 36 ;
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The answer is: " <span>36 " .</span>
________________________________________________________
_______________________________
Note: " (8 * 4) + 90 ÷ 9 " = " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .
We can rewrite the "fraction":
7 / [ (8 * 4) + 90 ÷ 9 ] ; as:
and can reduce this value to (and rewrite as): "
{ since: "
Note: The "fraction" :
{Since: "9÷3 = 3" ; and since: "6÷3 = 2" ).
So rewrite:
Note:
=
=
→ Note:
"
→ {since: "
=
______________________________
Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴ ;
=
_________________________________________________________
So, we can rewrite our expression as:
_________________________________________________________
Note:
_________________________________________________________
= (
= (
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Start with :
________________________________________________________
→ (
The "6" in the "
and the "6⁴ " in the "
→ {Since: "6⁴ / 6 = 6⁴ / 6¹ = 6⁽⁴ ⁻ ¹⁾ = 6³ ;
→ and we have:
→ The "
and since: any value, divided by "1", equal that same value; & since "any value, multiplied by "1"; equals that same value" ;
________________________________________________________
We have: " 6³ " .
________________________________________________________
Now, we multiplied this value, " 6³ " , by "
→ 6³ *
=
Note: The "6³ " cancels out to "6² " ; and the "6" cancels out to "1" ;
{since: "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
and since: "6 ÷ 6 = 1 " ; ________________________________________________________
→ The answer is: 6² = 6 * 6 = 36 ;
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The answer is: " <span>36 " .</span>
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