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Novosadov [1.4K]
3 years ago
8

If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th

e person would need to see an object at infinity clearly?
Biology
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

-3.50 meter

Explanation:

A nearsighted person uses concave lens.

Given -

Far point i.e distance of object = - 3.5 meter

Distance of image is not given . Hence we will assume that the image can be formed at any distance. We will take "di" = infinity

As we know

\frac{1}{f} = \frac{1}{di} + \frac{1}{df} \\

Substituting the given values in above equation, we get -

\frac{1}{f} = \frac{1}{infinity} + \frac{1}{-3.50}\\ \frac{1}{f} = 0 + \frac{1}{-3.50}\\ f = -3.50

Hence, the focal length of the contact lens is equal to -3.50 meter

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