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Genrish500 [490]
3 years ago
6

a preschool student finds a big bag of cookies and begins to take the cookies from the bag and hide them in her cubbyhole. after

hiding 3 cookies, she decides to keep count of how many cookies are actually in her cubbyhole. first there are 3 cookies. after pulling out more cookies, she then has 5 cookies, then 7 cookies, and then 9 cookies. however, she only knows how to count to 10! assuming she continues to pull cookies from the bag at the same rate indicated by the sequence of cookies above, how would the preschool student continue the pattern? describe the arithmetic sequence in this context.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:She will count the cookies by 2's

Step-by-step explanation:

You might be interested in
(x^3+10x^2+2)/(x+10)
SCORPION-xisa [38]

The quotient is x^2

The remainder is 2

Step-by-step explanation:

We need to divide: \frac{\left(x^3+10x^2+2\right)}{x+10}

The division is shown in figure attached.

The quotient is x^2

The remainder is 2

Keywords: Division of polynomials

Learn more about Division of polynomials at:

  • brainly.com/question/4390083
  • brainly.com/question/4786449

#learnwithBrainly

8 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
-5/4x+2/5=-13/30. What is the solution to ths equation
uysha [10]
2/3 is the answer to this problem.
8 0
3 years ago
Nine times a number
guapka [62]

Answer:

if we do 9 times a number that will be

9x

7 0
3 years ago
Read 2 more answers
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