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Genrish500 [490]
3 years ago
6

a preschool student finds a big bag of cookies and begins to take the cookies from the bag and hide them in her cubbyhole. after

hiding 3 cookies, she decides to keep count of how many cookies are actually in her cubbyhole. first there are 3 cookies. after pulling out more cookies, she then has 5 cookies, then 7 cookies, and then 9 cookies. however, she only knows how to count to 10! assuming she continues to pull cookies from the bag at the same rate indicated by the sequence of cookies above, how would the preschool student continue the pattern? describe the arithmetic sequence in this context.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:She will count the cookies by 2's

Step-by-step explanation:

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A trapezoid has an area of 22 square inches. The longer base measures 6 inches and the height is 4 inches. use the formula <img
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3 0
4 years ago
Find the directional derivative of the function at the given point in the direction of the vector v. h(r, s, t) = ln(3r + 6s + 9
vodka [1.7K]

Answer:

D_\overrightarrow{\rm v} h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})

Step-by-step explanation:

First,  let’s check to see if the direction vector is a unit vector:

||v||=\sqrt{(14)^{2} +(42)^{2} +(21)^{2}   } =\sqrt{2401} =49

It’s not a unit vector. therefore let's divide the vector by its magnitude in order to convert it into a unit vector:

\overrightarrow{\rm v}=(\frac{14}{49}\overrightarrow{\rm i})+(\frac{42}{49}\overrightarrow{\rm j})+(\frac{21}{49}\overrightarrow{\rm k})= (\frac{2}{7}\overrightarrow{\rm i})+(\frac{6}{7}\overrightarrow{\rm j})+(\frac{3}{7}\overrightarrow{\rm k})

Now, the directional derivative is given by:

D_\overrightarrow{\rm v} h(r,s,t)=\frac{\partial h(r,s,t)}{\partial r}\overrightarrow{\rm i} + \frac{\partial h(r,s,t)}{\partial s}\overrightarrow{\rm j} + \frac{\partial h(r,s,t)}{\partial t}\overrightarrow{\rm k}

So let's calculate the partial derivates:

\frac{\partial }{\partial r} ln(3r+6s+9t)=\frac{3}{3r+6s+9t}=\frac{1}{r+2s+3t}

\frac{\partial }{\partial s} ln(3r+6s+9t)=\frac{6}{3r+6s+9t}=\frac{2}{r+2s+3t}

\frac{\partial }{\partial t} ln(3r+6s+9t)=\frac{9}{3r+6s+9t}=\frac{3}{r+2s+3t}

Therefore:

D_\overrightarrow{\rm v} h(r,s,t)=(\frac{2}{7}\overrightarrow{\rm i})*(\frac{1}{r+2s+3t})+(\frac{6}{7}\overrightarrow{\rm j})*(\frac{2}{r+2s+3t})+(\frac{3}{7}\overrightarrow{\rm k})*(\frac{3}{r+2s+3t})

3 0
4 years ago
What is the answe ?????​
mestny [16]

Answer:

1) The first option

2) -9, -7, 6, 8, 10

3) Rise by 10 degrees

Step-by-step explanation:

Ascending is from smallest to biggest therefore you start with the smallest negative number and end with biggest whole number.

8 0
3 years ago
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