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netineya [11]
3 years ago
15

What do I do for this problem

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

To divide fractions, you need to multiply by the reciprocal. The reciprocal of 3/4 is 4/3, which is why the work is incorrect.

See attached:

You might be interested in
Sandra used partial products to find the product of 438 × 17 by multiplying 438 by 1 and 438 by 7 to get 3,066. Find the product
boyakko [2]

Let us determine the product of 438 and 17 by partial products.

Consider 438 = 400+30+8

and 17 = 10+7

So, 438 \times 17 = (400+30+8) \times (10+7)

438 \times 17 = (400\times 10)+(30 \times 10)+(8 \times 10) +(400 \times 7)+(30 \times 7)+(8 \times 7)

= 438 \times 17 = (4000+300+80+2800+210+56)

= 7446

Therefore, the product of 438 and 17 is 7446.

No, Sandra's answer is not correct.

Because she should have expressed 17 as (10+7), then if she multiplied (438 by 10) and (438 by 7). And, then added the results.Then her answer would be correct.

6 0
3 years ago
50 pts (and will mark brainliest)
Alex787 [66]

Answer:

c. 21/200

hope I helped!

6 0
3 years ago
Read 2 more answers
Simplify the expression
Natalija [7]

Step  1  :

 (23 x 2 -  5) • x 3

Step  2  :

Trying to factor as a Difference of Squares :

  Factoring:  8 x 2-5  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =  

        A2 - B2

Answer:

(8 x 2 - 5) • x 3

3 0
3 years ago
2. Solve x - 19 <81. Then graph the solution.
mr_godi [17]

Answer:

x<100

Step-by-step explanation:

The given equation is :

x-19<81

Adding 19 to both sides of the equation.

x-19+19<81+19

x<100

It means the solution of the given equation is less than 100. Hence, the attached figure shows the graph for the given equation.

4 0
3 years ago
75 + 13 + ?? = 140 i dont know what it is.
mixer [17]

Answer:

52

Step-by-step explanation:

140 - 13 = 127

127 - 75 = 52

Check your work:

75 + 13 + 52

= 140

8 0
3 years ago
Read 2 more answers
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