The answer will be 50 because if you are doing Area the formula is length times width therefore you would multiply all the numbers and you will end up with 50 feet cubed

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3 years ago

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The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and

storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of proportionality, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

$\frac{6.4^{2}}{156} k = 800$

$k=\frac{800.156}{96}$

k = 1300

For the similar beam:

$\frac{8.7^{2}}{L}1300=1300$

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0

3 years ago