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Nimfa-mama [501]
3 years ago
11

ASAP I NEED HELP PLEASE IM BEGGING YOU!!!!

Mathematics
2 answers:
gladu [14]3 years ago
5 0
Well, I won't give you the answers, but I'll help you with strategy. All you need to do is find a common denominator.

Good luck! :)
Katyanochek1 [597]3 years ago
3 0
All it is adding add both of the numbers that are on the top and then do the same
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Thirty students at Eastside High School took the SAT on the same Saturday. Their raw scores are given next. 1,450 1,620 1,800 1,
IRISSAK [1]

Answer:

Number of students who scored atleast 1700 but less Than 2100 = 17

Step-by-step explanation:

Given the data :

1,450 1,620 1,800 1,740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100

Class interval __ Frequency

1400 - 1599 ____ 5

1600 - 1799 ____ 7

1800 - 1999 ____12

2000 - 2199 ___ 3

2200 - 2399 ___ 3

Number of students who scored atleast 1700 but less Than 2100 = 17

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3 years ago
Is 4 1/2 yards of rope light enough for both the front and rear spoilers?
notsponge [240]
Yes because 1 1/4 + 1 1/2 = 2 3/4
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3 years ago
Please please please help me
Montano1993 [528]

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7 0
3 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

H_{0}:\mu=120 vs H_{1}:\mu\neq 120 (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}} which is normally distributed. The observed value is  

z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0
3 years ago
Six students are working on math 2/3 of them are working on fractions. How many students are working on fractions
Ostrovityanka [42]

Answer:

4 students are working on fractions

Step-by-step explanation:

5 0
3 years ago
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