The answer to you r question is 975. I hope this helps you
9514 1404 393
Answer:
D'(2, -1)
Step-by-step explanation:
Dilation about the origin by factor k multiplies each coordinate by that factor:
(x, y) ⇒ (kx, ky)
For k = 1/3, this is ...
(x, y) ⇒ (x/3, y/3)
D(6, -3) ⇒ D'(6/3, -3/3) = D'(2, -1)
Answer:6minutes
Step-by-step explanation:
3 hours =180min
180min divided by 30 windows is 6
Answer:
No
Step-by-step explanation:
We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.
quadratic equation is given by

It can be written as the product of linear factors

Where
are solutions of the given polynomial equation.
No , a quadratic polynomial equation can not have one real solution and one complex solution because complex root are always in paired not a single.
A quadratic equation have two roots only.
If a quadratic equation have complex root then the equation have both complex root .
If a equation have real root then it have both real.
Therefore, a quadratic equation can not have one real and one compelx solution.