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Elden [556K]
3 years ago
13

Please solve for x. I need this answered.

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

2.5x - 3 + 2x = 1.75x - 1.25x + 13

4.5x - 3 = 0.50x + 13

4.0x = 16

x = 4

Answer: 4

2. We'll assume those xs are in the numerator

(3/7)x - 1/4 + (3/7)x = (9/7)x - (3/7)x + 3/4 - 1

(6/7)x - 1/4 = (6/7)x  - 1/4

0 = 0

That's always true.

Answer: Any x is a solution.

Dovator [93]3 years ago
8 0

Answer:

2.5x - 3 + 2x = 1.75x - 1.25x + 13

4.5x - 3 = 0.50x + 13

4.0x = 16

x = 4

Answer: 4

2. We'll assume those xs are in the numerator

(3/7)x - 1/4 + (3/7)x = (9/7)x - (3/7)x + 3/4 - 1

(6/7)x - 1/4 = (6/7)x  - 1/4

0 = 0

That's always true.

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Two vertical angles are complementary. Statement is always, sometimes, or never true. Explain your reasoning
nikitadnepr [17]

Answer:

depends upon the degree of the angle

Step-by-step explanation:

vertically opposite angles are always equal like

80 = 80 sum is equal to 160 degrees not equal to 90

45 = 45 , sums equal to 90 degrees ,equal to 90

30 = 30 sum is equal to 60 degrees, not equal to 90

so we can say it depends what is the no of degrees if it is  45 only we can say  the vertically opposite angles are  complementary angle

7 0
1 year ago
If 4 peanut butter cups cost $0.96 and the peanut butter cups all cost the same amount, what is the price of each peanut butter
Oksanka [162]
We can set up an equation with x as the price of one cup:
4x=0.96
x=0.96/4=0.24

Each cup is $0.24

Hope this helped!
7 0
3 years ago
Read 2 more answers
PLEASE THIS WAS DUE 2 WEEKS AGO I NEED HELP
Agata [3.3K]

Answer: C

Step-by-step explanation:

4 0
2 years ago
Find the measure of the missing angle.
Nostrana [21]

180 minus 90 equals 90, divided by 2, the answer is 45 degrees

5 0
3 years ago
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

5 0
3 years ago
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