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Kipish [7]
2 years ago
13

Can someone please help me here

Mathematics
1 answer:
WARRIOR [948]2 years ago
5 0

\begin{cases} f(x)=3-3x\\ g(x)=x^2 \end{cases}\qquad \qquad \begin{array}{llll} f(~~g(x)~~)=3-3[g(x)]\\\\ f(~~g(x)~~)=3-3[x^2] \end{array} \\\\\\ f(~~g(x)~~)=3-3x^2\implies f(~~g(x)~~)=3(1-x^2)

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Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
7 0
2 years ago
Alex, Ian, and Ric together sold 48 tickets for the school fund-raiser. Alex sold 11 tickets and Ian sold 18 tickets. How many t
eimsori [14]
To determine the number of tickets that Ric sold, subtract from the total tickets sold the sum of the number of tickets sold by Alex and Ian. This is mathematically shown as, 

                        tickets (Ric) = tickets (total) - (tickets (Alex) + tickets (Ian))

                                  tickets (Ric) = 48 - (11 + 18) = 19

Hence, Ric sold 19 tickets for the fundraising. 
8 0
3 years ago
Read 2 more answers
The question about the metrologist
nadezda [96]
12% aka 12 days it didn't rain 

3 0
3 years ago
Solve the equation 0.1x+7=2​
yawa3891 [41]

Answer:

0.1x = 2-7

0.1x = -5

x = -50

5 0
3 years ago
Read 2 more answers
Complete the recursive formula of the geometric sequence -0.3, 0.9, -2.7, 8.1. ....
SSSSS [86.1K]

Answer:

(-1)ⁿ(3)ⁿ/10

Step-by-step explanation:

The first term a = 0.3, the second term, ar = 0.9. The common ratio r = ar/a = 0.9/-0.3 = -3.

From the general term of a geometric series,

U = arⁿ⁻¹

= (0.3)(-3)ⁿ⁻¹

= (3/10)(-3)ⁿ⁻¹

= (-1)ⁿ⁻¹(3)(3)ⁿ⁻¹/10

= (-1)ⁿ(3)ⁿ/10

5 0
3 years ago
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