Question

Can someone please help me here

Answer 1

$\begin{cases} f(x)=3-3x\\ g(x)=x^2 \end{cases}\qquad \qquad \begin{array}{llll} f(~~g(x)~~)=3-3[g(x)]\\\\ f(~~g(x)~~)=3-3[x^2] \end{array} \\\\\\ f(~~g(x)~~)=3-3x^2\implies f(~~g(x)~~)=3(1-x^2)$