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3 years ago

How to solve an algebraic expression by putting values of unknown

Mathematics

1 answer:

andrey2020 [161]3 years ago

7 0

Answer:

Step-by-step explanation:

Algebraic expressions tend to have atleast one unknown variable in it. In order to solve the expression we need to assign a fixed value to that variable or isolate it if the expression is equal to another value. For example, in the following expression we have the variable x, if we give it a value of 5 we simply solve like a regular expression...

5x + 3

5(5) + 3

25 + 3

Therefore, if we swap the variable x for the value of 5 we would get a value of 28 in this algebraic expression.

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Kelly has to read a 15 page poem she has read 10 pages so far,what fraction of the poem did she read?

Free_Kalibri [48]

Answer:

Kelly has read 2/3 of the poem.

Step-by-step explanation:

If you divide the 10 pages she has read by the total 15 pages, you get 0.66. Another way to get this is to put 10 over 15. Divide both the numerator and denominator by 5 to get 2/3.

5 0

3 years ago

Read 2 more answers

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .