Find an equation of the line given one point and the slope. (–10, –5);

1 answer:

7 0

You forgot to provide the slope but here is how you do this

the slope 5 = (y2 - y) / (x2 - x) but we know that (x2, y2) = (-10, -5)
=> (-5 - y) / (-10 - x) = 5 --- multiply both sides by (-10 - x)
=> (-5 - y) = 5 (-10 - x)
=> (-5 - y) = -50 - (5)x --- add +5 to both sides
=> -y = (-50 + 5) - (5)x --- multiply both sides -1
=> y = 5x + 45 --- this will be your equation.

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The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi

pshichka [43]

Answer:

$E(\bar{x}) = 28520$

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

$E(\bar{x}) = \mu = 28520$

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689$