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Aleks [24]
3 years ago
13

Fine the equation, in standard form, of the line passing through the points (3,-4) and (5,1)

Mathematics
1 answer:
Talja [164]3 years ago
5 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (3, -4) and (5, 1). Substitute:

m=\dfrac{1-(-4)}{5-3}=\dfrac{5}{2}\\\\y-(-4)=\dfrac{5}{2}(x-3)

The standard form: Ax+By=C

y+4=\dfrac{5}{2}(x-3)           <em>multiply both sides by 2</em>

2y+8=5(x+3)           <em>use distributive property</em>

2y+8=5x+15            <em>subtract 2y from both sides</em>

8=5x-2y+15          <em>subtract 15 from both sides</em>

-7=5x-2y

<h3>Answer: 5x - 2y = -7</h3>
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