We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
Answer:
I only know one way and its x = 7
Step-by-step explanation:
20 = 5( x -3 )
20/5 = x- 3
4 = x - 3
4 + 3 = x
7 = x
Answer:
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Answer:
y°= 51.30°
Step-by-step explanation:
Apply the formula for tangent of an angle
Tan Ф = opposite side length/adjacent side length
Tan y= 10/8
Tan y= 1.25
y° = tan⁻(1.25) = 51.34°
To the nearest tenth y°= 51.30°
