Answer:
a_n = 2^(n - 1) 3^(3 - n)
Step-by-step explanation:
9,6,4,8/3,…
a1 = 3^2
a2 = 3 * 2
a3 = 2^2
As we can see, the 3 ^x is decreasing and the 2^ y is increasing
We need to play with the exponent in terms of n
Lets look at the exponent for the base of 2
a1 = 3^2 2^0
a2 = 3^1 2^1
a3 = 3^ 0 2^2
an = 3^ 2^(n-1)
I picked n-1 because that is where it starts 0
n = 1 (1-1) =0
n=2 (2-1) =1
n=3 (3-1) =2
Now we need to figure out the exponent for the 3 base
I will pick (3-n)
n =1 (3-1) =2
n =2 (3-2) =1
n=3 (3-3) =0
Answer:1
Step-by-step explanation: 1/2 + 1/2 is 1
A 4 digit addends could have a 5 digit sum because of the rule of regrouping.
Regrouping is a situation where carrying and borrowing is involves. So let’s have an example
8999
<span>+5678
</span>14677
so in this example, we added 8999 to 5678.
9+8 = 17, so we bring down 7 and carry 1
9 + 7 = 16 + 1 = 17 , so again we bring down 7 carry 1
9 + 6 = 15 + 1 = 16, bring down 6 carry 1
8+5 = 13 + 1 =14, since this is our last number, bring down 14..
=> 14, 677
I am pretty sure its false. I think this becuase 1/2 goes into 3, 6 times, not 1 time. Hope that helps
