Answer:
I think x is 60 and y is 50.
Step-by-step explanation:
70 + 50 = 120
180 - 120 = 60
x = 60
50 + 50 = 100
70 + 60 = 130
130 + 100 = 230
230 - 180 = 50
y = 50
I hope this helps u! :D
Answer:
About 108 times
Step-by-step explanation:
Given:
An average soccer player travels 7 miles during a game
A typical field is 104 meters long.
To find:
How many times did the average soccer play travel the length of the field?
Solution:
An average soccer player travels during the game = 7 miles
First convert 7 miles into meters, 1 mile = 1609.34 meter
7 mile = 1609.34 \times 7 = 11265.41 m
Length of field = 104 meters
To find number of times average soccer player travel the length of the field, we will divide an average soccer player travels during the game by Length of field
11265.41 m 
104 = 108.32
Therefore, about 108 times average soccer player travel the length of the field
Answer:
A number line going from 0 to 4.5 in increments of 0.5
Step-by-step explanation:
This solution makes the most sense because 4.5 and 2.5 both have a decimal of 0.5
Answer:
Base=8.4 inches
Step-by-step explanation:
Area of triangular bandana is 38sq inches
Height of triangle is 9 inches
Area of ∆ =½×b×h
38=½×b×9
38×2=b×9
76/9=b
b=8.4 inches
Answer:
23.54 m
Step-by-step explanation:
Applying
cos∅ = adjacent(A)/hypotenuse(H)
cos∅ = A/H................ Equation 1
make H the subject of the equation
H = A/cos∅............ Equation 2
Given: A = 15 m, ∅ = 25°
Substitute into equation 2
H = 15/cos25
H = 16.55 m
Also,
tan∅ = opposite(O)/Adjacent(A)
tan∅ = O/A............Equation 3
Make O the subject of the equation
O = Atan∅.......... Equation 4
Substituting into equation 4
O = 15(tan25°)
O = 6.99 m.
From the diagram,
The height of the goal post before snap = H+O
The height of the goal post before snap = 16.55+6.99
The height of the goal post before snap = 23.54 m
