Question

A picture inside a frame is 2 inches longer than it is wide. The picture is in a frame that has a width of 3 inches on each side of the picture. If the area of the picture, including the frame, is 195 inches^2, find the dimensions of the frame.

Answer 1

Answer:

The dimensions of the frame are 15 in x 13 in

Step-by-step explanation:

Let

x ----> the length of the picture

y ----> the width of the picture

we know that

$x=2+y$ -----> equation A

The area of the picture, including the frame is

$A=(x+6)(y+6)$

$A=195\ in^2$

so

$195=(x+6)(y+6)$ ----> equation B

substitute equation A in equation B

$195=(2+y+6)(y+6)$

solve for y

$195=(y+8)(y+6)\\y^2+6y+8y+48=195\\\\y^2+14y-147=0$

solve the quadratic equation by graphing

The solution is y=7 in

see the attached figure

Find the value of x

$x=2+7=9\ in$

Find the dimensions of the frame

$x+6=9+6=15\ in$

$y+6=7+6=13\ in$

therefore

The dimensions of the frame are 15 in x 13 in