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Mice21 [21]
4 years ago
7

How do you solve 7.3t + 22equal 2.1t - 22.2

Mathematics
2 answers:
USPshnik [31]4 years ago
7 0
t = -17/2 = -8.500




Reformatting the input :

Changes made to your input should not affect the solution:

(1): "22.2" was replaced by "(222/10)". 3 more similar replacement(s)

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

(73/10)*t+22-((21/10)*t-(222/10))=0

Step by step solution :

Step 1 :

111
Simplify ———
5
Equation at the end of step 1 :

73 21 111
((——•t)+22)-((——•t)-———) = 0
10 10 5
Step 2 :

21
Simplify ——
10
Equation at the end of step 2 :

73 21 111
((——•t)+22)-((——•t)-———) = 0
10 10 5
Step 3 :

Calculating the Least Common Multiple :

3.1 Find the Least Common Multiple

The left denominator is : 10

The right denominator is : 5

Rzqust [24]4 years ago
6 0
The answer for your problem  is -8.5


You might be interested in
Joe measures side lengths of triangular canvas to be 22 inches, 10 inches and 11 inches. Could those be correct measurements?
SOVA2 [1]

Answer:

Incorrect measurement

Step-by-step explanation:

Given

Shape: Triangle

Length: 22in, 10in and 11in

Required: Determine if the measurements are correct

<em>For the measurement of a triangle to be true, the sum of any 2 sides must be greater than the length of the third side.</em>

<em></em>

i.e.

22 + 10 > 11 --- True

22 + 11 > 10 --- True

11 + 10 > 22 --- False

Since all three conditions are not true, then the measurements are incorrect

8 0
3 years ago
For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.
Sati [7]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.


<span>The sample space S in our problem is as follows: </span>

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

C(12, 2)=\displaystyle{  \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66

So there are in total, 5*66= 330 possible triples.

n(S)=330


The event E "selecting 2 freshmen and 1 junior" can occur in :

C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40 many ways.


so n(E)=40


P(E)=n(E)/n(S)=40/330=0.12



Answer: 0.12


 

4 0
4 years ago
-4x-15y=-17<br>-x+5y=-13<br><img src="https://tex.z-dn.net/?f=%20-%204x%20-%2015y%20%3D%20%20-%2017%20%20%5C%5C%20%20-%20x%20%2B
salantis [7]
To solve this system of linear equations we need a little trick called elimination steps are below

we are given the following system of equations
- 4x - 15y = - 17
- x + 5y = - 13
if you look at the x variables in both equations you can see that we can easily eliminate them by multiplying the bottom equation by -4 as so
- 4x - 15y = - 17
- 4( - x + 5y = - 13)
simplify and we get
- 4x - 15y = - 17
4x - 20y = 52
now we can combine like terms on each side with the x's cancelling and get

- 35y = 35
now divide off -35
y = - 1
great now we can go back to our original system and pick a equation and substitute y back in to find x lets use

- x + 5y = 13
so now we substitute y and get
- x + 5( - 1) = 13
- x - 5 = 13
- x = 17
x = - 17

now we put x and y into one coordinate (x,y)
so now our FINAL ANSWER IS
(-17,-1)
6 0
3 years ago
The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
Lunna [17]

Answer:

x = 2010

Step-by-step explanation:

It is difficult separating and organizing the data.  The best I can see is that the question is asking what is the value of x to make f(x) = t(x) true.  x = 2010  is a year in which enrollment was the same, 740, in both f and t.

3 0
2 years ago
Steps to solve 5[3(14.5+7)-3]-7.4
steposvetlana [31]
Hey there!

To solve this expression, you must follow your orders of operations or PEMDAS (Parenthesis, Exponents, Multiplication and Division, Addition and Subtraction).

In the case of  <span>5[3(14.5+7)-3]-7.4, you not only have parenthesis, but you also have brackets. To start, you would first simplify what is in the parenthesis:
</span><span>5[3(14.5+7)-3]-7.4
5[3(21.5)-3]-7.4

Now, simplify what is in the bracket, starting by multiplying 3(21.5) since multiplication comes before addition and subtraction:
</span><span>5[3(21.5)-3]-7.4
5[64.5-3]-7.4
5[61.5]-7.4

Now, multiply 5*61.5 since multiplication comes next:</span>
<span>5[61.5]-7.4
307.5-7.4

And finally, subtract what is left since it is your final operation remaining to get 300.1 as your final answer.

Hope this helps and have a marvelous day!
</span>
6 0
4 years ago
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