$\bf \cfrac{5}{\frac{1}{6}+\frac{1}{x+1}}\qquad \cfrac{}{\impliedby LCD\textit{ will be 6(x+1)}}\implies \cfrac{5}{\frac{1(x+1)+1(6)}{6(x+1)}}
\\\\\\
\cfrac{5}{\frac{x+1+6}{6(x+1)}}\implies \cfrac{\frac{5}{1}}{\frac{x+7}{6(x+1)}}\implies \cfrac{5}{1}\cdot \cfrac{6(x+1)}{x+7}\implies \cfrac{30(x+1)}{x+7}$

and you can expand the numerator if you wish, it won't be simplified further though.

6 0

3 years ago

ross has $500 in his savings account he is looking at two investment plans. under plan A, he will increase his plans about 150 a

GarryVolchara [31]

i dont know what you just asked

5 0

3 years ago

A polyhedron has 10 faces and 24 edges. Use Euler's Formula to find the missing number of vertices.

Grace [21]

Euler's Formula : V - E + F = 2

Given that F = 10 and E = 24

V - 24 + 10 = 2
V - 14 = 2
V = 16

Answer: Vertices = 16

6 0

3 years ago