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katrin2010 [14]
3 years ago
13

Solve the system of equations and choose the correct ordered pair. 2x+4y=16 2x-4y=0

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

(4, 2)

Step-by-step explanation:

Start by combining the equations

2x + 2x = 4X

4y - 4y = 0

16 + 0 = 16

4x = 16

x = 4

Now that you have one variable plug it back in to one of the original equations

2(4) + 4y = 16

8 + 4y = 16

4y = 8

y = 2

(4, 2)

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steposvetlana [31]

9514 1404 393

Answer:

  -203.1875

Step-by-step explanation:

The ends of the interval are ...

  (-4, g(-4)) = (-4, 1023 15/16)

  (1, g(1)) = (1, 8)

The average rate of change is the slope of the line between these two points:

  m = (y2 -y1)/(x2 -x1)

  m = (8 -(1023 15/16))/(1 -(-4)) = (-1015 15/16)/5 = -203 3/16

The average rate of change on the interval is -203 3/16.

5 0
2 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
PLEASE ANSWER THE PIC BELOW
Dmitrij [34]

Answer:

3.7

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
ivolga24 [154]

Answer:

-\sqrt{5}

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

  • One answer with positive square root
  • One answer with negative square root

For example, for the equation:

x^{2}=3

If we take the square root of both sides, the answers will be:

x=\sqrt{3} \text{ or } x= -\sqrt{3}

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and \sqrt{5}. Therefore, the 3rd root of the polynomial function f(x) had to be -\sqrt{5}

It seems you made error while writing option B, it should be - square root of 5.

4 0
3 years ago
Can someone help me please
laiz [17]

Area of trapezium= 1/2 × (a+b) × h

= 1/2 × (12 + 8) × 8

= 1/2 × 20 × 8

= 10 × 8

= 80 cm^3

Hope it helps you

3 0
2 years ago
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