<span>She needs to save an additional 108 quarters.</span>
Answer: Our required probability is 
Step-by-step explanation:
Since we have given that
Number of coins = 3
Number of coin has 2 heads = 1
Number of fair coins = 2
Probability of getting one of the coin among 3 = 
So, Probability of getting head from fair coin =
Probability of getting head from baised coin = 1
Using "Bayes theorem" we will find the probability that it is the two headed coin is given by
Hence, our required probability is
No, the answer is not
Answer:
m<1 =118 ~trust me I just finished this section
Answer:
Part 1
a. .27 < .50
b. .33 < .75
c. 4.60 > 3.89
d. .76 > .08
e. .09 < .11
f. 3.33 > 3.30
Part 2
.27(2)= .54
.50(1)= .50
.27(2)= .54 is larger than .50 because if it was money, .54 is greater than .50
Step-by-step explanation:
<h3>
Answer: 19</h3>
Explanation:
Let's break 110 down into its prime factors
110 = 11*10
110 = 11*2*5
110 = 2*5*11
We have three different prime factors that multiply to 110. However, the instructions say there are 4 integers that multiply to 110. To fix this, we can say
110 = 1*2*5*11
now we see that 1,2,5 and 11 multiply out to 110
They add to 1+2+5+11 = 3+16 = 19
