What is the image of (1, -6) for a 270° counterclockwise rotation about the origin?

Eight eagle stamps and two raccoon stamps cost $2.80. Three eagle stamps and four raccoon stamps cost $2.35. Find the cost of ea

nikklg [1K]

Answer:

Cost of each eagle stamp = $0.25

Cost of each racoon stamp = $0.4

Step-by-step explanation:

Given:

Cost of 8 eagle stamp and 2 racoon stamp = $2.80

Cost of 3 eagle stamp and 4 racoon stamp = $2.35

Find:

Cost of each stamp

Computation:

Assume;

Cost of each eagle stamp = e

Cost of each racoon stamp = r

So,

8e + 2r = 2.80........... Eq 1

3e + 4r = 2.35 ........... Eq 2

Eq 1 x 2

16e + 4r = 5.6 .........Eq3

Eq 3 - Eq 2

13e = 3.25

e = 0.25

Cost of each eagle stamp = $0.25

8e + 2r = 2.80

8(0.25) + 2r = 2.80

2 + 2r = 2.80

r = 0.4

Cost of each racoon stamp = $0.4

6 0

3 years ago

HELPPP

kiruha [24]

Answer:

90

Step-by-step explanation:

You would get 36 dollars from 90 liters.

The answer is in the photo.

6 0

3 years ago

3 3/4x2 4/5 simplest form

solong [7]

Answer:

The answer is 10 1/2.

Step-by-step explanation:

First:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

15/4×14/5

Next:

Apply the fractions formula for multiplication,

=15/4×14/5

=210/20

Last:

Simplify 210/20, the answer is

=10 1/2

Hope this helped! =)

6 0

3 years ago

the Length breadth and height of a room are 5 metre 4 metre and 3 respectively find the cost of whitewashing the walls of the ro

eduard

Answer:

its going to be 2&3(x+2)(x+3)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20

sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]$

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]$

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]$

Multiply the last row by 1/28 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate z from the second row by combining 3 (row 3) and row 2 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the second row by -1 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

$\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the first row by 1/2 :

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

8 0

3 years ago