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Vladimir79 [104]
3 years ago
5

Jeffrey biked to a bookstore at 12 mi./hr. but he took his time on his way home, going 8mi./hr. If it took him 20 min. to get to

the store, how many minutes did it take him to get back?
Can you explain how you got the answer, thanks<3
Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
It took him 8 minutes.
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I don't understand? (Questions 1 &amp; 3)
Afina-wow [57]
1. Yes. You are converting millimeters to centimeters.
3. "How many centimeters are in 5 inches" and "Five inches equals how many centimeters" are the answers here. It's the same question, just worded differently. 
5 0
3 years ago
2) The coordinates of the vertices of quadrilateral ABCD are A(-1,8),
Verizon [17]

Answer:

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

Step-by-step explanation:

When a point (h,k) is roated 180 degrees about the origin it becomes (-h,-k) which means that the new point after rotation is the negative of the previous.

Given vertices are:

A(-1,8),  B(0,4), C(-2,1), and D(-4,3)

The new vertices will be:

A(-1,8) => A'(1,-8)\\B(0,4)=> B'(0,-4)\\C(-2,1)=> C'(2,-1)\\D(-4,3)=> D'(4,-3)

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

3 0
3 years ago
Khan Academy Question
Mama L [17]

Answer:

84

Step-by-step explanation:

Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.

Angles PDA and ADR are complementary.

Angles ODU and UDR are complementary.

Angles ADR and UDR are given as congruent.

We can conclude that angles PDA and ODU are congruent.

By AA Similarity, triangles APD and UMD are similar.

DP/DM = PA/MU

3.75/10 = 4.5/MU

3.75MU = 10 × 4.5

MU = 12 (altitude of triangle DUO)

OD = OM + MD =  4 + 10 = 14 (base of triangle DUO)

area = base × height / 2

area = 14 × 12 / 2

area = 84

4 0
1 year ago
Factor completely x2 − 36. (1 point)
puteri [66]

Answer:

Solution given:

x²-36

x²-6²

(x+6)(x-6)

is your answer

6 0
3 years ago
Which of the following trigonometric ratios are correct?
den301095 [7]

Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.

  • sinA = opposite/hypotenuse
  • cosA = adjacent/hypotenuse
  • tanA = opposite/adjacent

Now that we know three basic ratio. Let's check each choices!

  • sin50° = d/c

This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.

  • sin50° = c/x

This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.

  • tan50° = d/c

This choice is correct! As ratio states, tanA = opposite/adjacent.

  • tan50° = x/c

This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.

  • cos50° = x/d

This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.

  • cos50° = c/x

This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.

Answer

  • tan50° = d/c
  • cos50° = c/x

Questions can be asked through comment.

Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.

Hope this helps, and Happy Learning! :)

8 0
3 years ago
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