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Alex Ar [27]
2 years ago
15

Which set of points lies on the the graph of the function.

Mathematics
2 answers:
meriva2 years ago
8 0

Answer:

(0,0), (-1, 1), and (1,-1)

Step-by-step explanation:

If you were to plot all the points they would all end up being on the green line

I hope this helped?

Rainbow [258]2 years ago
8 0

Answer: the answer is (0,0), (-1, 1), and (1,-1)

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Which of the ordered pairs in the form (x, y) is a solution of this equation?
Tju [1.3M]

Answer:

Both ordered pairs are solutions to this equation.

Step-by-step explanation:

If you plug in the x and y values given in the ordered pair, you make the left side of the equation equal the right for both pairs.

6 0
3 years ago
Dave rolls a die and flips a coin. How many outcomes are in the sample space?
kogti [31]
Well the are six sides and numbers on the dices and two sides on the coin so there would be 8 outcomes

5 0
3 years ago
Read 2 more answers
Can somebody please solve these for me I don't wana do it (thats why i am using so many points)
natta225 [31]

Down                            

6. 4,011                          

10. -94

11. 26

13. 178

15. -8

16. 6,861

18. 3,482

20. 385

22. 788

24. -5

25. 44

Across

1. -248

5. -9

7. 4,923

8. 90

9. 67

10. -912

12. 119

14. 16

15. -6

17. 743

19. 8,838

21. 47

23. 68

24. -884

26. 15

27. 7,284

4 0
2 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
PLEASE ANSWER ASAP!
muminat

Answer:

I think it volume will be 234m3

7 0
2 years ago
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