This graph shows a linear relationship

Mark and raquel were playing a word game.Raquel played the word math on a game board on a space marked’’triple points’.If her wo

Reika [66]

Answer:

111 points

Step-by-step explanation:

First, thing I like to do is to convert word problems into an eqaution or write down the important information. So, Math = 37 points and now the points are tripled because of where she placed the word. Also, tripled is implying that her base score for the word is 3 times the original value.

So, $37*3$

= 111 points.

5 0

3 years ago

Read 2 more answers

MARKING YOU BRAINLIST AND 5 STARS! A tire from Karen's car is shown below. Which is the closest to the distance traveled, in fee

Yuki888 [10]

Answer:

18.86 feet

Step-by-step explanation:

One rotation of the tire is equal to the circumference of the tire

The formula for circumference of a circle (remember that a tire is shaped as a circle) = πd

where

π = 22/7

d = diameter

The size of one revolution = 2 x 22/7 = 44/7 feet

The distance covered in one rotation of the tire is 44/7 feet

The distance covered in 3 rotations = (44/7) x 3 = 18.86 feet

3 0

3 years ago

Solving systems of equations by substitution -2x-3(6-11)=-7

Papessa [141]

Answer:

11

Step-by-step explanation:

Simplify both sides of the equation.

Subtract 15 from both sides.

Divide both sides by -2.

x = 11

3 0

3 years ago

A figure is created for semi-circles in a rectangle?

aev [14]

Answer:Learn to find the area of composite figures that contain circles and semi-circles. ... The area of the rectangle is 48 square inches. Next, recognize that ... Find the area of a figure that is made up of a square and a semi-circle.

Step-by-step explanation:I have made this reasoning: an eyelet consists of two semicircles and a rectangle (or two semirectangle), then a semicircle and a semirectangle ..But some irregular figures are made up of two or more standard geometric shapes. To find the ... We will break the figure into a rectangle and two semi-circles.

4 0

3 years ago

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

poizon [28]

Answer:

We have that $B = 0.3$ .

So

$0.3 = b + (A \cap B)$

However, b is a probability, which means that it cannot be negative. So no, P(A ∩ B) cannot be 0.5. It can, at most, be 0.3.

Step-by-step explanation:

Event A:

Probability that a student has a Visa card.

Event B:

Probability that the student has a MasterCard.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student has a Visa card but not a MasterCard and $A \cap B$ is the probability that a student has both these cards.

By the same logic, we have that:

$B = b + (A \cap B)$

In this problem, we have that:

$A = 0.6, B = 0.3$

(a) Could it be the case that P(A ∩ B) = 0.5?

We have that $B = 0.3$ .

So

$0.3 = b + (A \cap B)$

However, b is a probability, which means that it cannot be negative. So no, P(A ∩ B) cannot be 0.5. It can, at most, be 0.3.

8 0

3 years ago