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Colt1911 [192]
2 years ago
15

At Sunday’s Best Ice Cream in New Orleans, the price of Ice Cream was $4.00 for a large sundae. Due to the holidays, they are de

creasing their price by 12%. What is the new price for the large sundae?
Mathematics
1 answer:
dimulka [17.4K]2 years ago
6 0

the answer is $3.88

Step-by-step explanation:

because the ice cream was $4.00 and they subtracted it by 12% which would be $4.00 minus .12 which would give you $3.88

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Find the length of BC
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Answer:

13.3650978628

Step-by-step explanation:

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Here,

b=BC, p=AC & AB=12

Using the relation of cos,

cosx=b/h

cos27=BC/15

15cos27=BC

Using a calculator,

BC=13.3650978628

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2 years ago
In the equation y = kx, what does the variable k represent?
anyanavicka [17]

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I need help on 3and 5 PLS ASAP
AnnZ [28]

The 3rd answer is about 1 and the 5th one is about 3 hours

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3 years ago
The standard IQ test has a mean of 97 and a standard deviation of 17. We want to be
densk [106]

Let's call our estimate x. It will be the average of n IQ scores. Our average won't usually exactly equal the mean 97.  But if we repeated averages over different sets of tests, the mean of our estimate the average would be the same as the mean of a single test,

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σ = 17/√n

We want to be 95% certain

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2σ = 5

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√n = 2 (17/5)

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Answer: We need a sample size of 47 to be 95% certain of being within 5 points of the mean

6 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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