Between 0 and 1, add dashes so you have a total of 6 marks including 0 and 1. Then count 3 over and that would be 3/5.
<u>Answer:</u>
The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water
<u>Explanation:</u>
The rents for tubes for a person to use = $20
The rents for “cooler” tubes to carry food and water = $12.50.
The rent for a total of 15 tubes = $270
11 tubes whose rent cost $20 =
= 220
4 “cooler” tubes rent cost $12.50 =
= 50
Therefore for 15 tubes = 11 +4= 15
cost = 220 + 50
=270
The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of