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aleksandrvk [35]
3 years ago
15

ross has a rectangular garden in his back yard.He measured one side of the garden as 22 feet and the diagonal as 33 feet. what s

i the lengh of the side of his garden. round in nearset tenth of a foot
Mathematics
2 answers:
WARRIOR [948]3 years ago
6 0
We'd used the pythagorean theorem for this problem. Since the side length, diagonal, and missing side form a right triangle.

a²+b²=c²
22²+b²=33²
484+b²=1089
subtract 484 from both sides
b²=605
√b²=24.60
b=24.6 feet

Answer=24.6ft
liq [111]3 years ago
3 0
Same thing. 22^2+b^2=33^2
484+b^2=1089
b^2=605
b=24.60
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For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
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For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

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