4a and 14a can be combined with 3a! Hope this helped
Find an equation of the plane that passes through the points p, q, and r. p(7, 2, 1), q(6, 3, 0), r(0, 0, 0)
Alona [7]
Answer:
x - 2y - 3z = 0
Step-by-step explanation:
The cross product of vectors rp and rq will give a vector that is normal to the plane:
... rp × rq = (-3, 6, 9)
Dividing this by -3 (to reduce it and make the x-coefficient positive) gives a normal vector to the plane of (1, -2, -3). Usint point r as a point on the plane, we find the constant in the formula to be zero. Hence, your equation can be written ...
... x -2y -3z = 0
Answer:i am not sure
Step-by-step explanation:
This question is very hard to answer
the probability of choosing a student who plays soccer is 57%meanwhile the chance of picking a non soccer player is 43%.
Answer:
Step-by-step explanation:
The number of miles that he ran last week is m.
His goal this week was to run one mile more than twice the miles he ran last week. This means that his goal this week is
m + 2m = 3m
If he tripled his goal, it means that the number of miles that he ran this week would be
3 × 3m = 9m
An expression in simplest form to show how many more miles he ran this week compared to last week would be
9m - m = 8m