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tigry1 [53]
3 years ago
9

How can you identify a linear nonproportional relationship from a table, a graph, and an equation?

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer:21

Step-by-step explanation:

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Pleaseee i rlly need this one rn!!
bija089 [108]

Answer:

its 20 inches

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the area of the rhombus shown below? AC=17 BD=15 AB=11.2 Answers: A. 255 square units B. 190.4 square units C. 16 square
Lena [83]

Answer:

D. 127.5 square units

Step-by-step explanation:

AC=17

BD=15

AB=11.5

Diagonal (1&2) are given, base of the rhombus is also given.

Height is not given

Area of a rhombus given the diagonals

=1/2×d1×d2

Where,

d1=AC=17

d2=BD=15

Area of a rhombus=1/2×d1×d2

=1/2×17*15

=1/2×255

=127.5

D. 127.5 square units

4 0
3 years ago
Find the slope of the line that passes through the pair of points.
d1i1m1o1n [39]

Answer:

-7/5

Step-by-step explanation:

8 0
2 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Please help me or i will fail
dusya [7]
Find area of square: 7^2 = 49

Find radius of circle: 7/2=3.5

find area of circle: 3.5^2*3.14=38.465

Remove area of circle from area of square:
49-38.465=10.535 cm^2

Answer A is the correct one :)
4 0
3 years ago
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