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3 years ago

Y-3=2(x+1) Whats the missing value in the solution to the equation. (-1,__)

Mathematics

1 answer:

mixas84 [53]3 years ago

6 0

Answer: y = 3

Step-by-step explanation: y−3=2(x+1)

We know that x=-1 and we want to solve for y

Put in x=-1

y-3 = 2(-1+1)

y-3 = 2(0)

y-3=0

Add 3 to each side

y-3+3 = 0+3

y =3

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3 years ago

Determine the multiplicity of the roots of the function k(x) = x(x + 2)3(x + 4)2(x − 5)4. 0 has multiplicity −2 has multiplicity

wolverine [178]

Answer:

0 has multiplicity 1

-2 has multiplicity 3

-4 has multiplicity 2

5 has multiplicity 4

Step-by-step explanation:

The multiplicity of the root of a polynomial function, refers to the number of time the root repeats itself.

The given function is

$k(x)=x(x+2)^3(x+4)^2(x-5)^4$

To find the roots of this function, we equate the function to zero.

$x(x+2)^3(x+4)^2(x-5)^4=0$

We now use the zero product principle, to obtain;

$x=0$ , with multiplicity 1

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$\Rightarrow x=-2$ , with multiplicity 3

$(x+4)^2=0$

$\Rightarrow x=-4$ , with multiplicity 2

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$\Rightarrow x=5$ , with multiplicity 5.

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Answer:

Step-by-step explanation:

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4 years ago

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Answer:

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Step-by-step explanation:

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